19. a) 500N/kg
b) GPE = mgh
GPE = 50 x 10 x 4 = 2000J
c) KE = ½ m v2
KE = 0.5 x 50 x 2000 = 50000m/s2
Q3. A) GPE = mgh
GPE = 35 x 10 x 30 = 10,500J
B) KE = ½mv2
But KE (bottom) = GPE (top)
10,500 = ½ x 35 x v2
v2 = 600
v = 24.5m/s
C) because some of it got wasted by heat through friction
PFY p.121
Collins, p.91
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